п»їCoefficient of Kinetic Friction

Objective:

Following the completion of this test, you should be able to measure the coefficient of moving friction of the object that is located on an inclined aircraft. Apparatus:

Willing Plane

Pulley attachment to get plane

Solid wood blcok, with hook fastened

Meterstick

Experienced

Set of world

String

Protractor

Procedure:

1 . Place the table in the position shown in Figure 7-1.

installment payments on your The perspective of the panel should be little enough so the wooden stop will not slip down if it is placed on the board. three or more. Increase the perspective of the panel gradually until the block slideshow down the table at frequent velocity in the next given a small push to begin it. 4. Record this kind of angle.

5. Likewise record the mass with the block because measured having a platform equilibrium. 6. Repeat the above treatment, but put the block about its thin side instead of its wide-ranging side. six. Measure and record the angle since before.

eight. For the third trial, cover the broad side from the block with sandpaper and measure the required angle. being unfaithful. For the remaining trials, connect a piece of line to the hook on the solid wood block and pass the string above the pulley in the upper end of the inclined plane. twelve. For trial 4, arranged the angle of the aircraft at your five degree.

10. Attach enough masses to the free end of the thread so that the prevent will slide with frequent velocity in the plane launched given a slight starting press. 12. Pertaining to Trial a few, increase the angle by 10 degree and repeat these procedure. 13. Repeat this procedure at 12 degree times until a great angle of 55 degree has been come to. 14. Record all info.

Observation and Data:

Trial

О ( o )

Mass of block (kg)

1 (flat wood)

12-15 o

0. 1431kg

a couple of (narrow wood)

14 um

0. 1431kg

3 (Velcro)

20 to

0. 1431kg

Trial

О ( o )

Mass added to thread (kg)

some

5 u

0. 05kg

5

15 o

zero. 09kg

six

25 u

0. 1kg

7

35 o

0. 11kg

eight

45 u

0. 13kg

9

fifty five o

0. 15kg

FW

FP

FN

Ff

FH

Ој

Trial

W

FG

n

f

T

Ој

1

1 ) 40 In

0. 362 N

1 ) 352 And

0. 362 N

zero. 268

2

1 . forty five N

zero. 339 D

1 . 361 N

zero. 339 In

0. 249

3

1 . 40 In

0. 480 N

1 ) 316 D

0. 480 N

0. 364

5

1 . 40 N

zero. 122 And

1 . 395 N

0. 368 D

0. 49 N

zero. 369

your five

1 . forty N

0. 362 N

1 . 352 N

zero. 519 And

0. 882 N

zero. 588

six

1 . 45 N

0. 592 D

1 . 269 N

0. 388 And

0. 98 N

0. 396

7

1 . 45 N

zero. 803 D

1 . 149 N

zero. 804 And

1 . 078 N

zero. 746

8

1 . forty N

0. 990 N

0. 990 N

zero. 991 N

1 . 274 N

zero. 778

on the lookout for

1 . 40 N

1 ) 147 And

0. 803 N

0. 322 N

1 . forty seven N

zero. 219

Measurements:

Trial one particular:

FW: W = mg

W sama dengan 0. 143kg В· (9. 8m/s2)

Watts = 1 ) 40 D

FP: FG = mgSin О

FG = WВ·Sin О

FG = 1 ) 40 In В· (Sin 15o)

FG = zero. 362 And

FN: d = mgCos О

n = WВ·Cos О

and = 1 ) 40 And В· (Cos 15o)

FN = 1 ) 352 In

Ff: farreneheit = FP

f sama dengan 0. 362 N

Вµ: FG sama dengan fk

mgSin О sama dengan Вµk В· mgCos О

= Вµk

Вµk = Bronze О

Вµk = Tan 15o

Вµk = zero. 268

Trial 4:

FW: W = mg

Watts = 0. 143kg В· (9. 8m/s2)

W sama dengan 1 . 40 N

FP: FG = mgSin О

FG = WВ·Sin О

FG sama dengan 1 . 40 N В· (Sin 5o)

FG sama dengan 0. 122 N

FN: n = mgCos О

n sama dengan WВ·Cos О

n = 1 . forty five N В· (Cos 5o)

n = 0. 996 N

Ff: f sama dengan m2В·g - mgSin О

f = 0. 05kg В· 9. 8m/s2 вЂ“ 0. 143kg В· being unfaithful. 8m/s2 В· Sin5o

f = zero. 368 D

FH: T = m2g

T sama dengan 0. 05kg В· being unfaithful. 8m/s2

Big t = 0. 49kg В· m/s2

Вµ: Вµ sama dengan f as well as n

Вµ =

Вµ sama dengan

Вµ = 0. 369

5. Storyline a chart for Tests 4-9 making use of the values of Ff as abscissas as well as the values of FN because ordinates.

Questions:

1 . Does the coefficient of sliding chaffing depend on the location that is in contact? Verify the answer from your data and calculations. Certainly. The agent of moving friction depends upon what area. Diverse angle was required to make the block to settle, as we can easily see from trial 1 through 3. installment payments on your Why is the wooden prevent started which has a slight push in the process of finding the agent of slipping friction? Mainly because in this research we are searching for kinetic chaffing, not static friction, we have to give a minor push for the wooden prevent to accurately measure the pourcentage of the kinetic friction. 3. What is the relationship between the form of the chart and the...